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NEW QUESTION # 111
Examine the types and examples of relationships that follow:
Which option indicates correctly matched relationships? (Choose the best answer.)
Answer: C
NEW QUESTION # 112
Examine the description of the CUSTOMERS table:
You want to display details of all customers who reside in cities starting with the letter D followed by at least two character.
Which query can be used?
Answer: A
Explanation:
The LIKE operator is used in SQL to search for a specified pattern in a column. To find all customers residing in cities starting with 'D' followed by at least two characters, you need to use the LIKE operator with the appropriate wildcard pattern:
* A. SELECT * FROM customers WHERE city LIKE 'D_%'; The underscore () wildcard character in SQL represents a single character. The percent (%) wildcard character represents zero or more characters. So 'D%' will match any city starting with 'D' followed by at least one character (as there is one underscore).
References:
* Oracle Database SQL Language Reference 12c, specifically the section on pattern matching with the
* LIKE condition.
NEW QUESTION # 113
View the Exhibit and examine the structure of the EMP table which is not partitioned and not an index-organized table. (Choose two.)
Evaluate this SQL statement:
ALTER TABLE emp
DROP COLUMN first_name;
Which two statements are true?
Answer: C
NEW QUESTION # 114
Which two statements are true about the ORDER BY clause when used with a SQL statement containing a SET operator such as UNION?
Answer: B,E
NEW QUESTION # 115
You executed the following CREATE TABLE statement that resulted in an error:
SQL> CREATE TABLE employees(emp_id NUMBER(10) PRIMARY KEY, ename VARCHAR2(20), email NUMBER(3) UNIQUE, address VARCHAR2(500), phone VARCHAR2(20), resume LONG, hire_date DATE, remarks LONG, dept_id NUMBER(3) CONSTRAINT emp_dept_id_fk REFERENCES departments (dept_id), CONSTRAINT ename_nn NOY NULL(ename)); Identify two reasons for the error.
Answer: C,E
Explanation:
Explanation/Reference:
NEW QUESTION # 116
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